Subwoofer Question


Could having just one subwoofer (REL T/7x)with the crossover set around 60hz pull my image to the side that the sub is on?

maprik

That's what I was thinking. Those frequencies are supposed to be non directional right?

Yes, it did for me. No matter where I placed it, I could always tell it's location even when the crossover was set at 40hz.  It bothered me to the point of getting a second sub to balance it. Happy now.

Yes, this is why I often say a Stereo Pair of Subs, located near your mains, front firing to get the directionality/imaging that exists, i.e. where's the Jazz Bass Player?

you get fundamentals, harmonics, and overtones, i.e. 60/120/180/240 ....

diminishing in volume while increasing in directionality.

https://www.google.com/search?q=fundamentals+and+overtones&oq=fundamentals+and+overtones&gs_lcrp=EgZjaHJvbWUyBggAEEUYOTIKCAEQABgKGBYYHjIICAIQABgWGB4yCAgDEAAYFhgeMggIBBAAGBYYHjIICAUQABgWGB4yDQgGEAAYhgMYgAQYigXSAQg3Mzg4ajBqN6gCALACAA&sourceid=chrome&ie=UTF-8

 

@elliottbnewcombjr 

I understand that all notes have harmonics, but any harmonic above 60 Hz, (the op's crossover point) will be reproduced by his mains and not the sub, so I wouldn't think he would get directional cues from the harmonics, from the sub? The mains, yes, but not the sub. What am I getting wrong?

That sounds like it could be a relative phase issue.  Check polarity on all speaker and amp connections, including the sub.

 

To be clear, the OP was asking about imaging being pulled to one side.  Properly set up and set at 60Hz the imaging and image placement from your main speakers won’t be affected (other than imaging improvements subs can provide) but you may sense more weight or pressure coming from the area where the sub is located, which is a major reason why two subs are much preferred to one along with better dealing with room issues.  But that’s separate from imaging from your main speakers, so voices and other instruments should still appear where they normally do, and if not then that’s a sub setup problem.