Curious How These Nordost Speaker Cables Do What They Do


For a day and a half I’ve been listening to Nordost Red Dawn Rev.II cables in my system(Quad VA-One and Dynaudio Excite X14),courtesy of a friend who is in turn demo’ing some ungodly expensive upgrade...My reference are the Acoustic Zen Epoch..What these cables have brought to my system are:
The first thing I noticed is the music seems to come easier,ie:a touch louder than normal at low levels and it’s so clean I find I’m listening louder..
wider,deeper,and sharper defined imaging and staging...deeper,better defined and tonally richer bass...increased low level detail retrieval...a treble that is not as easy on the ears but seems better defined,almost sharp and I can see where some systems could move way to far into bright with these cables...
So I attribute the cleaner/sharper tone to the addition of high purity silver to the cable but I wonder what it is about the materials and construction that allow the bass,imaging and staging changes and especially the ease which music seems to come now?Any comments(from those who have found cables do matter)and NOT from those who believe they are snake oil PLEASE!!!
freediver
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Steve (Williewonka), your response to ieales about Ohm’s Law was correct, but he is correct in saying that equal currents exist in the positive and negative conductors connecting an amp and a speaker. (Although later in this post I’ll mention an extremely minor exception to that which might occur in the case of an active speaker).

For current to exist, there must be a "complete circuit," from source to load and back. In the case of an AC waveform, such as an audio signal, the direction of the current in both the positive and the negative conductors alternates every half-cycle, and the two conductors play an equal role in the transfer of energy from source to load. Energy is transferred in the form of an electromagnetic wave that is distinct from but is intimately associated with those currents, and that electromagnetic wave in turn propagates mainly in one direction, from source to load. (In the case of an amp/speaker interface some energy may also propagate from speaker to amp, as a result of "back-emf" produced by the drivers, or as a result of the release of energy stored in the inductive or capacitive components of the speaker’s impedance, or as a result of reflection effects that can occur at RF frequencies due to impedance mismatches).

An analogy that can be drawn would be to an ordinary light bulb. It consumes energy, of course, converting some of it into heat and some of it into light. But the amount of current entering it and leaving it via its two terminals, one of which is connected to AC "hot" and the other to AC "neutral," is identical.

The very minor possible exception I mentioned earlier is that in the case of a powered speaker a tiny fraction of the current in the positive conductor could conceivably return to the amp via a ground loop, part of which would consist of the safety ground conductors in the power cords of the amp and the speaker. In other words, to a very small extent, depending on the internal grounding configurations of the amp and the powered speaker, the AC safety ground wiring might be part of a relatively high resistance path that is in parallel with the negative conductor in the speaker cable, and it might thereby conduct a tiny fraction of the current in the positive conductor that would otherwise be returned to the amp by the negative conductor. (When two paths are present between a source and a load, current will utilize both paths, and at a given frequency will divide up between them in inverse proportion to their impedance at that frequency). But even in that case the amount of current leaving the amp will be identical to the total amount of current returning to it via whatever return path(s) is or are present.

Regarding "how Nordost cables do what they do," I have not studied them sufficiently or seen enough information about them to be able to provide meaningful comments at this time.

Best regards,
-- Al

@williewonka 
sorry you thought my post bombastic :-$ perhaps I get a bit carried away when fundamental laws are ignored.

the current (i.e. energy), or maybe even the voltage, in the neutral (i.e. minus) conductor cannot possibly be the same as the signal conductor.
It cannot be otherwise. As you state, energy cannot be created or destroyed. It changes state in the load.

The work is done by V pushing I through the load. If you measure a loudspeaker circuit, very little V is lost from either amplifier terminal to the speaker. Almost all V is across the load. Power is V x I. If the current were different in each leg of the cable, energy would either be gained or lost.

Apply a steady 1kHz 1V signal to a speaker. Regardless of where an ammeter is inserted in the circuit, the RMS current is the same.

In a DC circuit, V and I are in phase. In an AC circuit, V and I are not in phase if there is any L or C.  Cable LRC change the phase and relative amplitude in combination with amplifier and loudspeaker LRC.

Phase angle is dependent on the difference between L reactance XL and C reactance XC, which vary with frequency. In cables like zip cord XL & XC may vary by a factor of 100 to 1. Some exotic cables XL & XC may vary by a billion to 1. XL can vary by a factor of 10,000 and more between zip cord and exotic cables. Exotic cables should endeavor to have less inductance, but some are worse than zip cord.

Asymmetric cables have a different L & C relative to parallel or woven and as such affect the current phase differently. These phase changes may be euphonious with some amplifier / loudspeaker combinations, not so much with others.

Some put sugar in coffee and prefer the 'sweetened' result.

One cannot, in absolute terms, say it is better [more accurate].

One can only say it is more accurate if one compares the source wave form to the resulting sound at your ear!

@almarg - I think the lightbulb analogy is not a great example because the bulb is connected between two terminals that are both carrying an alternating voltage/current - I agree in that scenario there would be the same voltage on the +ve and -ve conductors

However in an amp, only the "SIGNAL PATH" of the circuit carries the alternating voltage/current
- the "power rail" is always at some +ve DC voltage
- the neutral rail is always at zero volts.(or should be)

The output terminal of transistor or tube performing the amplification carries the AC signal
- but the neutral side of the amp's circuit remains zero volts

The neutral conductor in the speaker cable, being connected to the neutral rail, should be at zero volts - should it not?

 I can see there would be  "a flow of electrical energy" that is from +ve output terminal - via the loudspeaker and cable - returning to the amp's -ve terminal. But somewhere along the way power has to be converted/consumed and that means either the current or the voltage has to change - doesn't it?

Thanks



No, that’s not correct, Steve.

First, keep in mind that a voltage must always be defined relative to some point, i.e., it exists between two points. It is not meaningful to simply think that "the neutral rail is always at zero volts."

In the case of a light bulb the terminal that is connected to AC "hot" is at 120 volts relative to the terminal that is connected to AC "neutral," which in turn is at or very close to zero volts relative to earth ground. In the case of a speaker cable the + wire is at some voltage relative to the - wire, depending on the signal at any given instant, and depending on the design of the amp the voltage on the - wire may or may not be at zero volts relative to the amp’s circuit ground, or relative to AC neutral, AC safety ground, and earth ground. For example, "fully balanced" amps and bridged mono amps both have full amplitude signals on both their + and - output terminals, with the voltages on those terminals differing from each other simply in that they have opposite polarities.

The current that is provided to a speaker by an amp, as well as the current that is provided to a light bulb by the incoming AC, both result from a voltage **difference** that is applied between the two conductors. The fact that one conductor may be at zero volts relative to some reference has no relevance to that.

Also, ieales comment above that relates to this ...
If the current were different in each leg of the cable, energy would either be gained or lost.

Apply a steady 1kHz 1V signal to a speaker. Regardless of where an ammeter is inserted in the circuit, the RMS current is the same.
... is absolutely correct.

Best regards,
-- Al