@richardbrand Said:
AC or Alternating Current flows for a short period in one direction, then reverses direction repeatedly. Analog audio signals are AC, and current flows as a result, in speaker and interconnect cables alike. Current is the net movement of electrons in a direction.
So you are saying in a closed circuit the signal flows back and forth from the source to the load. Correct?
If the source is a CDP and the load is an Integrated Amp, using only one channel, the signal leaves the output on the hot wire of an IC, flowing back and forth, flowing to the input of the Amp, through the input circuit of the preamp, and then returns on the return wire back to the CDP output... Correct?
As for the current the "net movement" of charge, it will measure the same on the hot wire as the return wire in the IC back to the analog output section of the CDP. Correct? This whole event takes place in the wires... Correct?
I'm confused with this theory of the signal flowing back and forth in the wire from the CDP, through the input circuit of the preamp section in the integrated Amp, and then back to the CDP output circuit. Is this the way you say it works? How does the input section in the preamp, for a better word, extract the signal from the IC as it travels through the closed circuit, flowing back and forth, back to the CDP? And what happens to the signal that returns back to the CDP?
Wow! Is that how you are saying it works?
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It's makes a lot more sense the signal travels in the spaces between the two conductors in one direction from the CDP >>> to the input section of the preamp section of the Amp, in the form of EM Waves at near the speed of light in a vacuum. The signal does not return to the CDP.
The wires of the IC are needed to guide the signal energy from the CDP to the preamp. The transmission line is the two wires. You need the wires to create an Electric field and a Magnetic field to create electromagnetic fields outside of the wires. The CDP supplies the voltage for the E field. My understanding, the B (magnetic) field is created by the electric charge flowing in the closed circuit. (Flowing, slower than cold maple syrup) And the electric charge does not flow back and forth in the wire. It's vibrating + - and hardly move at all in the wire.
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You asked in a post about the size, thickness, of the wire. Simple ohms law I = E/R. The bigger the connected load, more current, amperes, the bigger the AWG of the wire needed. More Current, Amps, in the closed circuit, the stronger the magnetic fields. The bigger the load, (lower resistance), the greater the energy transfer from the source to the load.
Energy is what makes the light bulb light, not the current. Current is not consumed by the load. Proof, it returns to the source. Current measures the same on both sides of the load.
Energy is not consumed, it is transferred. It does not return to the source.
Not sure you read this post of mine on page 2. I assume you have heard of the Late Ralph Morrison.
Ralph Morrison What is Electronics
Using your theory how things work, You have to disagree with everything Morrison said that I quoted of his. All of the books he wrote and published, wrong... How many books have you written? And no I haven't written and published any books.
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Are you familiar with the "School of Physics, The University of Sydney"
Understanding Electricity and Circuits:
What the Text Books Don’t Tell You
Ian M. Sefton
I.Sefton@physics.usyd.edu.au
https://www.vicphysics.org/documents/teachers/2002Sefton.pdf
Do things in the white paper sound familiar? Is Ian M. Sefton wrong too?
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