What actually determines volume power? Is it watts?


I have a Yamaha AS-3200 amp. It sounds beautiful and has a really good open sound. The problem is I like my music loud since I live alone and typically I have the volume 70% and with some recordings it is not high enough. I need a amp that has more power/volume.

The AS-3200 is 200 watts at 8 ohms. I see many amps, even much more expensive ones (like the Yamaha M-5000), are also at around 200 watts per a channel at 8 ohms. I am going by 8 ohms for my speakers and also the worse case scenarios. Does this mean if I had a more expensive class AB amp like the M-5000 I would still be listening at 70% volume and getting the same power/loudness? If not, then what actually determines the volume power if not watts?

dman777

Showing 1 response by audiorusty

dman77

For every 3 db SPL increase in output volume requires a doubling of the amplifier watts being used. So if your speaker sensitivity is 88 db, which means that it takes 1 watt of amplifier power to drive that speaker output to 88 db at 1K Hz measured 3 feet away. It will take 2 watts to drive it to 91 db, 4 watts to get to 94 db, 128 watts to get to 109 db and 256 watts to get to 111 db and that is before we consider the effects of the inverse square law which states that you will loose 6 db of SPL for every doubling of distance from the source.

To answer your question more directly, it’s a combination of amplifier power, speaker sensitivity, source level, room size, music type (low frequencies will eat more power than high) and I’m sure there are other factors I don’t know about. A 200 watt amp is a 200 watt amp and will drive a speaker close to the same volume regardless of price, but a better amp may do it a little cleaner, with better low end or  better peak output, etc. etc.