Replacing Vintage Lights

Remove bulbs, read the numbers on base, get new bulbs.

yep,sure do,either unsoldier or unplug the burnt bulb & take it to a tv repair shop,ive had nothing but good luck with my tv repair shop matching up bulbs from modern & vintage equipment alike.

the best part about dealing with a tv repair shop instead of a hifi repair shop is that you will not pay outrageous prices for a 10 cent bulb.

example.

i has a mcintosh mc150 amplifier rebulbed at my local hifi shop,the cost was $140 & i had to leave it for 8 days to be rebulbed.

2 months later i bought another mcintosh mc150 amplifier that needed rebulbing but this time i took it to my tv repair shop,the cost was less than $20 & they did the repairs while i waited.

another good spot to look is an industrial electrical supply house,the one near me stocks allmost every bulb ive ever needed.

mike.

I have replaced several of my burnt out lights with LED's. But you have to measure the voltage for the lamps, then use Ohm's Law to figure out what series resistance to use. With Led's you can also choose color. I like the blue ones - replaced the lights in a Yamaha C-4 Preamp with Blue LED's - looks great...

industrial electrical suppliers such a Newark, Allied Electronics, Mouser, DigiKey are all good sources for bulbs. You may even find what you need via Radio Shack.
One hint about pilot lamps: once you determine the type of bulb (voltage & current rating) if you can then find a bulb of slightly higher voltage rating & if it will physically fit in, that bulb will last almost indefinitely because it is dissipating slightly less power. It will however, have a slightly reduced brightness which is typically a non-issue.
Joe's LED suggestion is also a good one; if you're familiar with basic electronics & soldering it's not that hard to figure out. Start with the measured supply voltage, figure on 15 to 20mA LED current, calculate the dropping resistor vaule as:
supply volts, minus ~1.5V for the LED. The voltage remainder dropped arcoss the power resistor / divided by the LED current = the resistance value.
Example: 20V supply - 1.5V LED = 18.5 V remainder.
18.5V / 0.02A = 925 ohms (use a 1k-ohm resistor).
Power is calculated as I * E: 18.5V * 0.02A = 0.37 watts.
This calls for a 1/2 watt resistor @1k ohm resistance value.