My understanding of capacitors is that they store energy. Does this mean that my Due amplifier is just as powerful as the on paper more powerful Atoll in300?No. It just means that the energy storage for the output section will have less noise so less intermodulation at full power.
But one thing left out is the voltage of the power supply with all these different amps. Its important because in the formula for electron storage in a capacitor, the voltage dominates the equation
W (work) =1/2 (C xVsquared)
where C is capacitance and V is voltage. So by raising the voltage a little, you raise the storage a lot!
BTW, its the storage in the supply that is usually what is being quoted when the manufacturer states the 'amps' it has- for example 80 amps. If we use that figure we see that its obviously not output power, since using the power formula
P=Isquared x R (where P is power in watts, I is current in amps and R is resistance in ohms)
If we give the amp the benefit of the doubt and state a 1 ohm load, then the power is simply the current squared. No-one makes a 8400 watt amp. Into 2 ohms this would be 16,800 watts....
So a value like that is actually the current that flows for 10mS when the power supply is shorted out. Its an easier way of understanding the energy there instead of the 1st formula I showed above.
Our MA-2 amplifier has 72,000uf at 150 Volts... it can easily do that 80 amps and its a 220 watt tube amp. Capacitive values like this are there solely because the amp sounds better when they are.