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bypassing a crossover in a two-way

i am not a tech person so forgive any ignorance. i want to bypass the crossover in a simple and cheap two way, because the main driver is the same one used in the manufacturer's crossoverless design.

the manufacturer gave me the following instructions: "A 0.68uf cap in series with the tweeter + lead is all you need,, - to the - binding post." I'm not sure what this means. looking into the speaker i can see the black and red wires leave the speaker leads and inter the crossover network. leaving the crossover are two sets of black and white wires, one set going to the leads on the woofer, the other connected to the single wire from the tweeter.

am i to cut the speaker wire before it reaches the crossover and then insert the cap? if so, how, specifically, do i these three connections to a single cap (1. the input from the speaker leads, 2. the output to the woofer, and 3. the output to the tweeter)? i am not able to visualize his statement in relation to what i've described as the inside the speaker cabinet. i've looked elsewhere on the web but to no avail. i realize it is simple but just don't have the background.

any help would be very much appreciated.
thomp9015

Showing 1 response by s7horton

s7horton
1,077 posts
 
Disconnect the (+) lead off the tweeter and solder one end of the cap on the tweeter and the other end onto the positive binding post.

You'll probably have to use a small wire from the end of the new cap to the binding post. As the lead from the new cap most likely isn't long enough to reach the binding post.

It sounds like there must be a series crossover in this cabinet and in order to complete the circuit but pull the tweeter portion you, you have to do this.
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