I must have remember the formula incorrectly--I thought it was 10 log (P1/P2).
It is. However we are dealing with voltage, not power, and it is 20log(V1/V2) as Mulveling explained. Since for a given load power is proportional to the square of voltage, the logarithm gets multiplied by an additional factor of 2 when calculating from voltages.
log(X squared) = 2(log(X))
Regards,
-- Al