Record Cleaning Using Vacuum Machine for Cleaning and Ultrasonic for Final Rinse


Readers unfamiliar should reference Precision Aqueous Cleaning of : Vinyl Records by Neil Anton, 3rd Edition, March 2024 available for free on line.  It will provide specific details that I will reference in passing here for brevity.  Specifically, look at Chapter III - Solution Preparation; Chapter VIII - Vacuum Cleaning Machines; and Chapter IX - Ultrasonic Cleaning Machines.  

Summary of Methodology (for very dirty records):1. Preclean 2. Pre-Wash 3. Rinse 4. Vacuum (partial) 5. Tergitol clean 6. Vacuum (partial) 7. Ultrsonic Final Rinse (2minutes) 8. Final Vacuum Dry  

Summary of Methodology (for new to v.good records): 1.Tergitol clean 2. Vacuum (partial) 3. Ultrasonic Final Rinse (2minutes) 4. Final Vacuum Dry                        

Materials Used:  Distilled Water obtained for local grocery store, Tergitol 15-S-9 (0,5ml/L); Liquinox (5ml/L).

Machines:  VPI MW-1 Cyclone; HumminGuru Nova

Brushes:  Osage, VPI, Record Doctor

billstevenson

Showing 2 responses by oberoniaomnia

@antinn how do you get from mass of pure dehydrated Tergitol to film thickness of 31 nm? Tergitol is something like a C33 hydrocarbon chain and generally hydrocarbon chains are around 1 nm thick (e.g., sugar). I failed to find any information on volume of dry Tergitol.

I guess you could calculate number of molecules in 315 ng of T (MW ~550-650 depending on T variant), assume size of around 1 nm2, convert LP surface to nm2, divide LP nm2 by #of T molecules and get stack of T molecules per surface area and assume that stack has unit height of 1 nm.

@antinn Thanks for the details.

With pure T density rho of 1 (close enough, easy math) 1g/mm3, 0.3 mg have volume of 0.0003 mm3 = 3 x 10e-4 mm3. Record surface ~ 0.3 m2 = 3 x10e5 mm2

3 x 10e-4 mm3 : 3 x 10e-5 mm2 = 1 x 10e-9 mm = 10e-12 m, which is subatomic. (Angstrom is 10e-10 m). So you have scattered molecules of T on the surface, not even a film. Thickness of impurity is that of the size of the molecule, ~ 1 nm.

As an upshot of this, rinsing with distilled water to get concentration of T down by factor 10–100x is a non-issue. It does not matter. At 100x higher concentration, "film" thickness is still in Angstrom order of magnitude, so still scattered molecules. 

Even if my calculations are not precise (record surface is 28 cm2 minus center label area guesstimated 20 cm2), our calculations give different result by factor of 10'000x, which is pretty significant, IMHO. My math skills are not that great, still don't know I passed calculus, but this looks pretty straightforward to me. 

I think the problem step is going from weight to thickness, which IMHO is not supported. Going from weight and density to volume, and volume/area to thickness is more direct. my 2c.