True bi-amping of speakers from different amps to different drivers, ie woofers and mains, would show a doubling of resistance when adding them together, which is not the case, because they are still the same to each set of drivers. Bi-wiring accomplishes nothing. That means that no improvements or degradations will be heard,k unless, of course, the wires were too small or too resistive to begin with. Simply doubling wires to the same terminals does not double the impedance. It halves it. However, since he mentioned he was using shorter wires, for example say to half the original length, the impedance would be the same as before, and for other lengths, easy calculable with simple multiplication and division skills.
Possibly dumb question: can I use two cable runs for each channel, not bi-wired?
I'm moving my components into another room, in order to shorten the existing 30 foot cable runs to about 10 feet,
and will run the cable through the wall between adjoining rooms. I'm wondering if I can make use of the resulting "left-over" lengths of cable by doubling up each run, utilizing one pair of binding posts for each side. Has anyone tried this? Question #2: should the pairs be jointly terminated,or should I use bananas coupled with spades, so that there are 4 terminations at each post? I haven't sen any references to this in the past, so it may well be in violation of some basic rule of physics, but I thought I'd ask, anyway.
and will run the cable through the wall between adjoining rooms. I'm wondering if I can make use of the resulting "left-over" lengths of cable by doubling up each run, utilizing one pair of binding posts for each side. Has anyone tried this? Question #2: should the pairs be jointly terminated,or should I use bananas coupled with spades, so that there are 4 terminations at each post? I haven't sen any references to this in the past, so it may well be in violation of some basic rule of physics, but I thought I'd ask, anyway.