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musical fidelity/conrad johnson - chan separation

hi there,

ok - so i've been looking for a preamp and I'll bringing home a couple to listen to tonight: conrad-johnson p 14 and a musical fidelity a3.2 (I know, apples and oranges...)

My question is this: what exactly does the channel separation of >85dB at 1kHz mean? I understand that the higher the channel separation=less channel leakage but I'm really having a hard time comparing that number to anything and conrad-johnson doesn't even offer a figure for it or even a s/n ratio :\

is this something I should even be concerned with? any input would be appreciated...greatly! :)

Just in case - the rest of my system:
rotel rb1080
b&w nautilus 804's
_s00ka_

Showing 1 response by edesilva

edesilva
768 posts
 
dBs are ratios--I am presuming that means for a signal applied to the right channel, you will get that signal on the left channel at 85 dB below the level of the right channel. Since 3dB=double, the level of the undesired signal on one channel would be 1/60,000,000 (give or take a bit) of the desired signal on the other channel. Pretty negligible in my book...

I think... but I could be totally wrong...
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