One capacitor, one inductor and one resistor indicates a first order crossover. The resistor is probably a 4-ohm because (maybe) one driver is probably 4-ohm and the other 8-ohm. The resistor is in series with the 4-ohm driver to give a nominal 8-ohm speaker impedance.
For first order filters, the 4.7uf cap lets through frequencies above 4kHz. The formula is
F = 1/{2*pi*C*R) where R=8 ohms
The inductor will let through frequencies under 4kHz
L = F/(2*pi*R) = 0.3mh at F=4kHz, R=8ohms
All of the parts here are critical. The function of the crossover is to roll off the frequencies, not to abruptly cut them. The order (capacitor quantity) determines how fast the frequencies roll off.
The way they work is: the capacitor is charged at a certain rate from the signal. If the rate of charge from the signal is greater than the capacitor's ability to absorb the charge, the excess frequencies are passed through the capacitor. As the frequency of charge decreases, the capacitor's ability to store it is greater than the charge rate - so these frequencies do not pass. This frequency is the F in the above equation.
The inductor, which is a coil, creates a magnetic field when a frequency charge is passed through. As the voltage rate of change (frequency) is increased, the inductor creates a proportionately stronger magnetic field which increases the resistance. As the frequency decreases, the magnetic field is created less frequently and the inductor settles down and lets current flow easier.
For first order filters, the 4.7uf cap lets through frequencies above 4kHz. The formula is
F = 1/{2*pi*C*R) where R=8 ohms
The inductor will let through frequencies under 4kHz
L = F/(2*pi*R) = 0.3mh at F=4kHz, R=8ohms
All of the parts here are critical. The function of the crossover is to roll off the frequencies, not to abruptly cut them. The order (capacitor quantity) determines how fast the frequencies roll off.
The way they work is: the capacitor is charged at a certain rate from the signal. If the rate of charge from the signal is greater than the capacitor's ability to absorb the charge, the excess frequencies are passed through the capacitor. As the frequency of charge decreases, the capacitor's ability to store it is greater than the charge rate - so these frequencies do not pass. This frequency is the F in the above equation.
The inductor, which is a coil, creates a magnetic field when a frequency charge is passed through. As the voltage rate of change (frequency) is increased, the inductor creates a proportionately stronger magnetic field which increases the resistance. As the frequency decreases, the magnetic field is created less frequently and the inductor settles down and lets current flow easier.