Disconnect the woofer


If I was to unhook the wires to the woofer of my (non-biwireable) 3 way speakers, would the crossover parts that make up the low pass to the woofer still be using up energy from my amp, or is there no energy loss since the circuit is not completed?

I am thinknig of active bi-amping the woofers with another amp and letting the mid/tweeter run off my orignial amp.
koestner

Showing 1 response by magfan

Inductors and capacitors do not soak up power and get hot in the sense that a resistor does......and therefore don't produce lots of heat.
However, given improper design, you have a situation where the current and voltage are out of 'sync'....This can be measured in degrees of displacement. At 90 degrees, for example (never seen in a loudspeaker) there is NO POWER delivered to the load. So, even if you had a 500 watt amp and 93db sensitive speakers, they would be silent, at least at the frequency where the 90 degree displacement occurred.
Lesser amounts of displacement result in power loss as well.
This is called POWER FACTOR and is the real reason some speakers can be considered a BAD LOAD, not simply low impedance.... Or my Maggies, though power hungry, would be considered such a bad load. They present a fairly benign phase angle situation above and below the 600hz xover.
This is also the difference between VA and power in Watts, also measured as the product of volts and amps.....