The formula to determine the differences in dB is
dB = 10* log10(power_ratio)
For voltage it is:
dB =20 * log10(voltage_ratio)
For the 2V system compare to the 6V
dB =20 *log10(2/6) = -9.54 dB
Every 10 dB is 1/10 the power (or about (1/3)**2 ) and will sound about 1/2 as loud. Hope this helps.
dB = 10* log10(power_ratio)
For voltage it is:
dB =20 * log10(voltage_ratio)
For the 2V system compare to the 6V
dB =20 *log10(2/6) = -9.54 dB
Every 10 dB is 1/10 the power (or about (1/3)**2 ) and will sound about 1/2 as loud. Hope this helps.