The speakers have four spikes each. How would the cones be attached to the speakers? I would like to include a photo of the spikes but don't see how to do. Thanks.
Spikes on tower speakers
This is my first post here, just getting involved in the earlier stages of serious stuff. I recently bought a pair of Piega p4L MKll speakers. They sound great, at least according to my perhaps unsophisticated ears.
My question/problem: The speakers have spikes on them that cannot be removed because the previous owner glued them to the base. Becaue of the spikes, the speakers are very unstable on the carpet in my listening room. I need something that the spikes will go into so that the speaker towers will be more stable. So far, neither plywood nor small metal speaker spike pads have worked. Am now considering carbon speaker spike pads and hockey pucks to get the spikes into and then a bigger base, such as wood or even granite/marble.
I would greatly appreciate any suggestions that would solve this problem.
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Actually, it doesn’t matter if they have four as long as the cones are taller than the spikes, but do use only three cones of you decide to try this. The cones don’t have to be attached. The cones have flat upper surfaces, so the speakers simply rest on them. The original metal TipToes or similar were about 1.5 in. in diameter. Alternatively, you could simply use double sided tape to secure them lightly or a bit of Bluetac. It’s the same principle as using cones under electronic components. It works well. |
Spikes are for coupling, if you have a suspended wooden floor, it will cause the entire floor to resonate.
As for the speaker moving? Some folks have invoked the Great Isaac Newton, but didn't bother to do any Newtonian Science. Your speakers weighs 14kg, a typical 15cm paper driver has about 8.5g (0.0085kg) of moving mass and an extension of about 4mm. F = mass*acceleration Work = Force*distance or Work = mass*acceleration*distance The force acting on the cone and the speaker body are equal and opposite, and the work done by the cone on the speaker is expressed as: 0.0088*acceleration*.004m = -14*acceleration*distance cancel acceleration and simplify the left 0.0000352 = -14*distance -0.000002514m = distance = -0.0025mm your speaker will move 2.5 microns at full excursion. This is in a frictionless un-damped setting. If you are curious, a 12" woofer typically has a moving mass of about 100g, or about 11.7 times the mass of a 6" cone. In this case, the same enclosure would move about 30microns, which is in the vicinity of a 12MHz sound wave.
We get enough hand-waving junk science from Amir over at ASR, let's not infect this fine forum with more of the same nonsense.
Spiking to a concrete floor often improves the damping of a speaker, isolating a speaker from a suspended floor improves the damping of the floor. What works best in your system depends on your system and room.
I like the idea of setting the speakers on a board of some kind be it a cutting board or a hunk of MDF. Use your feet of choice on the board, spikes will require you to drill some holes and add inserts, isolators can be inexpensive "pucks" you put under the board. I suggest these things It is possible they are already thicker than your spikes are long and you wont need a platform at all, or maybe you can add something under them like machine felt or heavy cardboard to give them a bit of extra lift. I probably would not go with anything fancy, these are (according to the Piega manual) entry level speakers.
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@joshua43214 I never said spike speakers to suspended wooden floors. Indeed I said don't spike speakers to suspended wooden floors. For the reason you state. But if, as I do, you spike speakers to a concrete slab laid on a screed in the ground the vibrations in the speakers caused by the music signal will be damped by the mass of the Earth which is 5.972 × 10^24 kg. If we take the speaker as having mass of 100kg, then the small movement in the speaker will cause a movement of the Earth that is 100,000,000,000,000,000,000,000 times smaller. I think we can take that as no movement. The statement near the end of your post is therefore correct, save that you can replace 'often' with 'always'. |
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