Yes, putting my previous comment and Stan's good comment a little differently, to be sure it is clear to everyone:
A wire gauge that is adequate to support the run length and the amount of current being delivered to the speakers, as well as a gauge that is larger than that, will result in essentially all of the amplifier's output voltage appearing across the speaker terminals. That happens because the wire's resistance is much smaller than the speaker's impedance (impedance essentially meaning the speaker's resistance at the particular frequencies being delivered, to oversimplify a little bit).
If the wire gauge is too small, meaning the wire is too thin and its resistance too high, then a significant fraction of the amplifier's output voltage will not appear across the speaker terminals, and will appear across the resistance of the wires instead.
Regards,
-- Al
A wire gauge that is adequate to support the run length and the amount of current being delivered to the speakers, as well as a gauge that is larger than that, will result in essentially all of the amplifier's output voltage appearing across the speaker terminals. That happens because the wire's resistance is much smaller than the speaker's impedance (impedance essentially meaning the speaker's resistance at the particular frequencies being delivered, to oversimplify a little bit).
If the wire gauge is too small, meaning the wire is too thin and its resistance too high, then a significant fraction of the amplifier's output voltage will not appear across the speaker terminals, and will appear across the resistance of the wires instead.
Regards,
-- Al