Something doesn't seem right about this...


When a speaker cable is designed with the positive lead(s)
intertwined with the negative (I'd name names but almost everyone does it),
won't this cancel out some signal?

When an amplified audio signal pulses down the + wire (to your speaker)
it does some work (i.e. makes some sound) then exits in the - (minus)
wire to ground and completes the circuit.
If these wires are next to each other, the incoming signal (+) will be affected by the outgoing (-) won't it?

What am I missing?
128x128dweller

Showing 1 response by kijanki

Two wires, positive and negative, together reduce electromagnetic and capacitive noise pickup. They also reduce noise radiated from these wires. It is because noise is being picked-up (or radiated) by both wires that are at opposite polarities thus cancelling. Twisting wires greatly helps because both wires are exposed more evenly to external fields. Speaker output is also (in most cases) an input to amplifier and wire acts as antenna for noise.

Twisting wires reduces inductance, as Al stated, but also increases capacitance. In case of the speaker wire capacitance does not play as much role as inductance. In interconnects it is just the opposite but twisting is still used to reduce noise pickup.