I would feel pretty confident that the amp can supply 500W into 4 ohms, for the following reasons:
1)This review indicates that it can.
2)The first paragraph that starts on page 10 of the user manual sort of implies that it can.
3)The specs on the last page of the user manual indicate a maximum output voltage of 65 volts, and maximum output current of 20 amps. I believe those are peak numbers, rather than the conventionally used rms values. The rms equivalents for those numbers are 46 volts and 14.1 amps. 500 watts into 4 ohms requires 44.7 volts and 11.2 amps rms, those numbers being less than the specified capabilities.
That would apply to the unbalanced input. I suspect that an amplitude of 1.4 volts on each of the two signals at the balanced input (meaning a 2.8 volt differential) would also result in full power, but I'm not certain of that. The other possibility would be a 1.4 volt differential, or an amplitude of 0.7 volts for each of the two signals.
Best regards,
-- Al
1)This review indicates that it can.
2)The first paragraph that starts on page 10 of the user manual sort of implies that it can.
3)The specs on the last page of the user manual indicate a maximum output voltage of 65 volts, and maximum output current of 20 amps. I believe those are peak numbers, rather than the conventionally used rms values. The rms equivalents for those numbers are 46 volts and 14.1 amps. 500 watts into 4 ohms requires 44.7 volts and 11.2 amps rms, those numbers being less than the specified capabilities.
What is the input sensitivity for the X250 for full out-put, balanced and single-ended?The user manual indicates a gain of 30db. That is a voltage gain of about 31.6 times. 250W into 8 ohms, or 500W into 4 ohms, corresponds to an output of 44.7 volts. 44.7/31.6 = approximately 1.4 volts sensitivity (the input voltage required for maximum rated output power).
That would apply to the unbalanced input. I suspect that an amplitude of 1.4 volts on each of the two signals at the balanced input (meaning a 2.8 volt differential) would also result in full power, but I'm not certain of that. The other possibility would be a 1.4 volt differential, or an amplitude of 0.7 volts for each of the two signals.
Best regards,
-- Al