Need help with high pass filter


Does anybody have a formula to figure out the right uF for a capacitor and k-ohm for resistor (ground) to make a130Hz high pass filter between pre-amp and poweramp with an imput impeadance of 33 kohms? Your help would be greatly appreciated!!
arni

Showing 3 responses by 1439bhr

Let's talk circuit topology. For a high pass filter (HPF), you will need the capacitor (C) in series in the signal path from preamp to power amp. The additional resistor (R) can go in one of three places: (1) it could bridge across the preamp outputs, but this will have no effect on the filter characteristics (2) it could parallel C, but this would change your HPF from a true high-pass characteristic to a shelved filter that merely emphasizes high frequency, or (3), it could bridge across the power amplifier input. This is the only logical place, and it serves to better define the actual load seen by the network (the specified input impedance is a "nominal" value. Your mileage may vary). The resistance (R) parallels the power amp input impedance (we'll assume it's all resistive) Rin. The filter resistor R should be chosen to be smaller than Ri, but larger than the lowest load impedance Rlow allowed by the preamp manufacturer. I'd pick R = sqrt(Rin*Rlow) as a compromise. You can compute the effective termination load of the HPF as Reff = 1/((1/R)+(1/Rin)). The cutoff frequency of the HPF will be f=1/(2*pi*Reff*C). Transposing this gives C = 1/(2*pi*f*Reff). Given your values, and assuming Rlow = 10 Kohms gives R=18.2 kohms and Reff = 11.7 kohms. This, in turn gives a required capacitance of 0.10 uF. If you decide to use a 15 kohm resistor, Reff = 10.3 kohm, and the required capacitance is 0.12 uF. If you do not include resistor R in the HPF circuit, then Reff = Rin, and the required capacitance is 0.037 uF (Joegio, check the batteries in your calculator; they're running a little low :-)
Whoops, one more possibility I forgot concerning circuit topologies: the added resistor could be placed in series in the signal path. That would make Reff = R + Rin in the calculation for C in my previous post. The downside of this is that an attenuated signal voltage is presented to the power amp input, limiting the maximum volume available from the system (that may or may not be an issue, depending on the size of R compared to Rin).
Looks good. The thing to realize is that the actual cap value may vary quite a bit from the nominal value. Ordinary commercial caps may have tolerances as large as +50 / -20%. Tolerances on good resistors may be as large as 5%, or less than 1% for "precision" resistors. If you have access to a capacitance bridge, you may want to measure the actual cap value and adjust resistance to suit. That's what "hand picked" components mean. As far as construction technique, take a peek at a couple of electronics hobbyist magazines to get a feel for typical techniques, or visit your local electronics parts store or even Radio shack, nose around the construction hardware sections and ask a few questions. Better yet, ask around and find someone who's into ham radio. Chances are they know something about constructing homebrew electronics. An ugly but effective solution would be a small plastic "project box" drilled for installation of RCA plugs, with the parts mounted on a small piece of perforated board mounted in the box via machine screws and standoffs, or use a "terminal strip", which is a piece of Bakelite plastic with solder lugs mounted on one side and a couple of mounting lugs on the other side (this used to be used a lot in vacuum tube TVs and radios employing "point to point" wiring.) Have fun!