how can a cheap cd drive equal a fine transport?


Once a "perfect" file is on a HD, I grasp why playback may be better than reading data from a drive in real-time. But when ripping a cd, the digital data stream is read by a cd drive, i.e, a flimsy, cheap transport. The best transports produce a data stream with less error, or jitter. Large amounts of error correction are audible, so presumably, the less error correction applied, the better. So at the point where the cd is read by a drive, before applying error correction, before it even reaches a HD (or the prior optimal solution, a Genesis Digital Lens), how can a cheap computer drive produce a data stream comparable to a good transport? How can programs which try it 64 times, or whatever, produce a better result? Aren't they just using error correction (or checksum algorthms to determine which attempt got the best result, out of many error-laden reads) compensate for high initial error rates? Are fine transports almost pointless, now?
lloydc

Showing 1 response by trebejo

Yeah, a good DAC is where to put the cash. Ripping CDs to the hard drive is the way to go nowadays, apparently the checksum can even be done by comparing to values that can be found online (since lots of people are ripping the same CD).

EAC is the classic choice for a Microsoft OS, and as for Macs there are some choices, I use XLD.