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Helmholtz resonator equation help? Anyone?

Don't know if this forum is the right place for this question, as I'm trying to figure out how to build a bass trap with this formula. But thought I'd try.
Anyways, does anyone know or know how to work the helmholtz resonator formula, for constructing a perforated box?
I seem to be getting conflicting results with my mathematical formula proceedures for some reason. Don't know why. Also, does anyone know where I can find a "plug in" or whatever to simplify this process? I'm a bit "puter ill-literate", sadly.

I have the following formula, but am getting conflicting "right answers" when I try to work it. Here's what I'm using from F.Alton Everest's Master Acoustics Handbook:

F = (200)x square root of (P/(D)x(t))

In which F = target frequency,hz
P = perforation percentage
t = effective hole lenght, inches, with corretion
applied
= (pannel thickness) + (.8)x(hole diameter)
D = depth of air space, inches.

Now, this same book says that if you use common peg board, with a .18 inch (3/16ths) thickness, and same hole diameter, with 1" spaced holes on center, at a depth of 4"(er, 3.625" on 2x4 studs), your reasonant fequency is around 420hz. I seem to get anything but that when I calculate!
Maybe someone has some input here? I know it's an "off the beatten path" post at that.
Any input will be greatly appreciated!
Please no PM's, just respond here for all to see
russno5067
flrnlamb
508 posts
 
Ok, it's official! It appears my mathematics has developed a sever case of rust! Either that, er I'm just not good. Probably the later (lol)
I can't seem to figure "backwards", trying to figure for "DEPTH", rather than from the forumula in the book, which figures from "frequency".
I'm trying to do this by hand first, so I can see it work.
Anyone want to confirm how to break down the forumla
F=200 x the square root of (P)/(D)x(T), so I can figure back for D? So, would it be D = (P)/(T)x((200/F)squared)?
I don't seem to be doing this right.
I really need to figure for depth, rather than from Frequency.
Thank you
flrnlamb
508 posts
 
Can anyone take the first formula I had which is:

F = 200 x the square root of ((P/(D)x(T))

And then, while knowing the other variables, switch the equation around to solver for D, rather than F?
Thanks
danish
30 posts
 
Which comparison chart are you referring to? I'm assuming the table starting on page 223? I tried a few random lines in their examples and they worked out correctly.

D = (40000/F^2) * (P/T)

If you have Excel you could easily set this up using the "goal seek" function to get the result you want.

Let me know if you need any help.
russno5067 OP
5 posts
 
Thanks for the help guys. I think I was just lazy with most of this. I think I got the forumulas figured out to solve for any variable.
Flrnlamb? If you need any equation help, er whatever, let me know. I'll shoot you over what I came up with anyway.
I'd check em out thouroughly though before trying however, as my math is "suspect" at best.(lol!)
dbld
297 posts
 
I don't know if this could help, but the link below may provide some info. It deals mostly with cylinders, but there are many other links on the page that could lead you to something that might help.

http://hyperphysics.phy-astr.gsu.edu/hbase/waves/opecol.html#c2

Dave
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