If you were to connect the outputs of the CD player to a typical input impedance of say 47K, and if the CD player is putting out an average of say 1 volt while playing a disc, the player would be supplying an average of about 0.00002 amperes (i.e., 20 microamperes) into that load impedance. Which is so little that it would seem very unlikely to make any difference, compared to breaking the player in without a load.
IMO. Enjoy the new player!
-- Al
