After Market Power Cables - Gold or Snake Oil?


Myself and a collegue of mine have been discussing the potential benefit(s) of using after market power cables with hifi equipment. I claim that since the majority of home owners gain their power from the everyday wall socket, how does the addition of a short length of 'expensive' cabling make any appreciable difference to the sound quality. Are we kidding ourselves and buying into marketing hype or is there some scientific truth to the matter? I am a musician/recordist who understands the fundamentals of electricity and sound reproduction.
checkmate110

Showing 3 responses by audioengr

Amplifiers demand current from the power-line when the capacitors in their power-supplies become momentarily discharged due to high-current transients in the music signal. This discharge condition must be quickly recharged from the power-line, through the power-supply transformer, or a voltage sag will occur. Such voltage sags can cause audible distortion at the loudspeakers. If the power-line has significant series inductance in the path from the power panel to the amplifier, this can prevent the capacitor bank from recharging in time to prevent a voltage sag from occurring at the amplifier output transistors. With a low-inductance cable, the voltage drop across the cable will be insignificant during high-current transients, minimizing the voltage sag. This allows all of the current needed by the output transistors to be supplied when they need it, resulting in fast, dynamic response to transient signals.

What is important to understand is that typical rubber cords have many times the inductance of the ROMEX in the wall, so adding a rubber power cord is like extending the ROMEX from 20 feet to 30-40 feet. Here is a calculation based on actual measurements:

A typical 6-foot 14 AWG rubber cord and 25 feet of ROMEX has inductance of 7.2 uH and resistance of 235 mohms, ignoring the plug resistance effect. Therefore, the voltage drop at 20kHz will be I*(wL+R)= I*(.905+.235) = I*(1.14). With a 6-foot Magnum2 and 25 feet of ROMEX, the inductance is 5.9 uH and the total resistance is 147 mohms. This is an 18% reduction in inductance and a 37% reduction in resistance. The voltage drop for this combination will be I(wL+R) = I(.741+.147) = I(.888). So at a fixed dynamic current I, the voltage drop in the entire power feed at 20kHz is 22% smaller with a Magnum2 power cord. I would consider 22% to be significant. The reality is even more compelling. When you add in lower plug and receptacle resistance and the fact that the di/dt on the power cord will have spectra well above 20kHz with some amplifiers, the low-inductance cord makes an even bigger difference.
Checkmate110 - You are correct, the total inductance from the panel is what matters.
M_Cassar - there is one other possible benefit of a power cable and that is filtering. This filtering can be only on the ground wire or the current-carrying wires. Ground-wire filtering makes a lot of sense, since there should not be any AC current on the ground anyway, since this constitutes ground-loop noise. Filtering on the current-carrying wires, hot and neutral is another matter. I personally do not believe in it (and my designs do have hot/neutral filtering), but I suppose some components with poorly designed power supplies could benefit from this. Certainly not amplifiers though.