Why 24/7 warm-up period on amps?


The 24/7 warm-up period on amps seems excessively unsupported. Yes, an amplifier (pre-amp or power amp) will change it's circuit factors as the init heats up since the resistive and capacitive values stabilize...but for months on end? Do we still have a "warm" heart for tubes, that do indeed need to get "hot" to work right?

A capacitor charges up based on it's RC time constant, which is in the SECONDS range, not days. OK, if you add the heat sink area so the heat going out is stabilized I can see maybe an hour or so. My DNA-225 gets HOT in thirty minutes, at which point it's steady state. That even assumes it doesn't have temperature correction circuits to make it more stable, and less subject to change over time.

Break-in periods are hard to judge what people think is happening. Circuit P/N junction temps get hot pretty fast. A mechanical device like a speaker or phono cartridge, sure, they will work-in just like a well used rubber band. But silicone? Factory burn-in is designed to find weak components that degrade outside of SOP ranges, not to "center" their attributes in a normal stable circuit. Did someone forget to add enough heat sink compound to a PNP or NPN transistor, for instance?

Assumming break-in is real, not to be confused with the warm-up period, once it's done it's done. After that it would be warm-up only time. And, warm-up is a simple thermodynamic process. It only takes so long to warm-up and it isn't "days" on end. Maybe hours...if even. Once things are to temp the circuit constants are set. What else is changing? A heat sink is designed to warm-up and hold a delta temperature where the measured performnace is flat. A small amp (pre-amp gain stage) has smaller heat sinks for this reason. Heat and resistance are related, so you have to pick a temp and hold it. You design to THAT attrubute on the component.

Wire conditioning in the amp? ( go here - http://www.angelfire.com/ab3/mjramp/golopid/grain.html) As well as several other sites and textbooks.

The DC path is just that, DC. The magic is the purity of the DC, not the wire moving it around. You either have the right voltage and current capability (wire size)or you don't. Once the amp is on, the wires capacitance hardly matters. PP, PE or Teflon dielectrics only ionizes-tree and fail at break down voltages around impurities, not below that. You do not want to ever ionize the insulation in normal practice.

AC is an interesting issue. The AC complex signal is ALTERNATING differently at each and every frequency point, so the magnetic and electric fileds keep switching with respect to frequency. So the dielectric can not have polarity, or current "direction". The dielectric will not "align" to anything.

Grain structure in copper does not change unless you melt it. It's set when the rod is made. Annealing just resets elongation by improving homogeneous grain alignment, not the grain boundary characteristics since wire is resitive annealed at well below the temp that would fully reform the grain boundary around impurities in the copper. Oh, all modern 9/16" rod copper is made in induction ovens and is essentially OFC grade. All wire is drawn from that rod. Modern copper is also "high conductivity". Again, these terms are throw backs to days gone by with coke furnaces and open air annealing to critical temps where impurities could be picked up, changing the grain boundaries around impurities.

I also notice the people seem to tout TEFLON over Polypropylene or polyethylene dielectrics. Teflon costs more, it is higher temperature capable to 150C-200C (like 80C on polyethylene isn't enough in electronics) but Teflon has a worse dissipation factor and loss tangent. Using Teflon has a more NEGATIVE influence on electricals than olefins. Teflon's velocity of propogation at RF frequencies way above 1MHz is 70% verses 66% for solid olefin dielectrics. But that is at RF. And, you can nitrogen foam either to negate that advantage of Teflon at RF, but NOT Teflon's high price, loss tangent or dissipation factor. Capacitance adjusted Teflon is a poor choice. So the important factors are capacitance, dissipation factor and loss tangent. We can easily fix the velocity of propagation. PE and PP is superior across the board and cheaper (that's probably the problem!).

Good circuits are good circuits. Could you even make a circuit that had electricals parameters that were undefined till it ran, "forever"? Nope, can't be done. Design would then be a game of chance. I don't think that it is. Stabilized junction temps are used to set electrical componenet attributes with respect to temperature. You can design heat sink characteristics to place "hot" components where thet need to be temp wise to meet a circuit requirement. A poorly designed amp that allows thermal run-away under load isn't appropriate and isn't made...for long. There is indeed a circuit junction temp that rather quickly defines the measurable performance of the circuit, and a STABLE delta attribute approximation(s) when a circuit is designed. You know going in what they will be in operation steady state.

So, I hear my speakers and phone stage "break-in. And they don't go backwards once thet are broken-in. They can, in fact, get worse and simply break-down! But my amp sounds fine in short order. The circuit reaches a thermodynamic steady state and we're off to the races. I just can't see a circuit that needs 24/7 "on" period to stabilize...unless it just isn't stable. To me that's a poor design, and one subject to possibly serious load induced instability when the circuit falls outside of the stable design region(s).

I'd sure like to see MEASURED attributes that support 24 /7 warm-ups on sound. I have yet to see any measured data to support this. Show me components used in amps that take MONTHS to reach stady values. I have read PLENTY to support first to third approximation(s) on amplifier circuits ambient thermal temperature stability points. Many circuits are designed to run "cold" and have inverse circuit systems to keep changes due to temp deltas away. This way, you have a more stable circuit at all times. The opposite designis technically UNSTABLE till it gets to temp. This also limits what you can do as it can't blow-up when it is cold BEFORE it gets hot and stable. So the circuit is a compromise.

So just what are the resistive, inductive and capacitive break-in periods on quality components used in a circuit? In God we trust, all else bring data.- unknown
rower30

09-14-11: Almarg
Paperw8, the fundamental misconception you have, which ultimately leads you to incorrectly assert that first order filters roll off at 3db/octave, is the notion that the numerical db value describing the ratio of two signals applied to a given resistive load will be different depending on whether voltage or power is being considered.

while you have posted many informative comments on this forum, one of my criticisms of you is that you post references that you seem to have only half-read, and then draw conclusions that don't stand up to a closer reading of the reference.

as to the first reference you cited, the writer presented a first order RC filter. he also showed the transfer function for the filter. so if you really do want to know the behavior of the circuit, don't take my word for it, just look at the equation and figure it out for yourself.

if you look at the *asymtotic* behavior of that circuit shown (and by "asymtotic" i mean frequency>>RC), the transfer function is:

v_out=(C/f)*v_in

where C is a constant and f is frequency.

let me first establish that an "octave" means a doubling of frequency. given that, for each doubling in frequncy, the output voltage v_out is reduced by half relative to v_in. so if you want to compute the decibel change in voltage for each octave:

v_dB=10*log(v_out(f)/v_in(f))
v_dB=10*log(1/2)/octave
v_dB=10*(-0.3)/octave
v_dB=-3dB/octave

that's the result; it's not subject to your opinion or my opinion, that's just what it is.


09-14-11: Almarg
I'll mention, btw, that early in my career as an electrical design engineer, a great many years ago, I had the exact same misconception, until my boss enlightened me.

The value of that number is one and same, whether voltage or power is being considered. For a given resistive load, reducing the applied voltage by a factor of 2 reduces power by a factor of 4 (as you agree), and the change in signal level is 6db. Period.

what "signal level" are you referring to?

i've got a deal for you almarg, if you're so convinced that i am wrong, then rip an *unedited* copy of my postings and send them to henry ort and ask for his comments on them.

that will be interesting...
09-14-11: Paperw8
v_dB=10*log(v_out(f)/v_in(f))
v_dB=10*log(1/2)/octave
v_dB=10*(-0.3)/octave
v_dB=-3dB/octave

that's the result; it's not subject to your opinion or my opinion, that's just what it is.
As I said, you have a fundamental misconception which underlies all of the differences in our positions.

The number "10" in all of your equations that I've quoted above should be "20," since you are computing the number of db based on a voltage ratio. I've explained it, Kijanki provided a proof of it, and Ott provided a proof of it. I've recommended multiple times that you do further research to convince yourself of it. Until you understand that the number 10 is the wrong number to use in converting voltage ratios to db, we will get nowhere.

Regards,
-- Al

09-14-11: Almarg
The number "10" in all of your equations that I've quoted above should be "20," since you are computing the number of db based on a voltage ratio. I've explained it, Kijanki provided a proof of it, and Ott provided a proof of it.

kijanki, did you say what almarg says you said? if power is reduced by half is that a 3dB reduction or a 6dB reduction.

the problem is that you're not clear on what ort is talking about. as to ort, when ort talks about dB he is talking about *power*. in the webite that you cited ort says "The dB is a logarithmic unit expressing the RATIO of two powers". what ort also says as an aside "Although the dB is defined with respect to power, it has become common practice to also use it to express voltage or current ratios". so while he is saying that some people compute dB for voltage, or current, ort feels that, properly stated, dB is a ratio of power levels. so when ort talks about dB, he is talking about a ratio of power levels. so when he refers to the 20*log(v2/v1) equation, the dB is a dB in *power*; that's why he calls it a "Derivation of dB as a Voltage Ratio". ort isn't saying that 20*log(v2/v1) is a voltage dB, what he is saying is that it is a power dB expressed as a ratio of voltages.

in ort's view, it is not proper to talk of dB as a ratio of voltages, but he recognizes that many people do so. so what i would expect ort would say about my postings is that it is not strictly proper to talk of a dB in voltage but that it is commonly done even though the only proper dB computation is for power. thus, when you refer to the 20*log(v2/v1) equation, you have to be clear that, in ort's view, "This is only correct, however, when V1 & V2 (I1 & I2) are measured across the same value of impedance".
if power is reduced by half is that a 3dB reduction or a 6dB reduction.
I'm sure Kijanki will answer the part of your question that was directed to him, but in the meantime I'll state that if power is reduced by half that is a 3db reduction. That same 3db reduction also reflects voltage being reduced to 0.707 of its original value.
ort isn't saying that 20*log(v2/v1) is a voltage dB, what he is saying is that it is a power dB expressed as a ratio of voltages.
I have tried to explain in my previous posts that it is incorrect to distinguish between a "voltage db" and a "power db." A db is a db.

Regards,
-- Al
Paperw8 -

Voltage ratio in electronics is, and always has been 20log(v2/v1). Pretty much anything other than power is always 20dB(k2/k1) including sound pressure, sound level etc.

-3dB of voltage means 0.708 of a value. 12dB means ratio of 4, 20dB i ratio of 10 etc. All electronic equipment is scaled that way (oscilloscopes, multimeters, oscillators, dividers etc.). When you press +20dB button on the oscillator output will always jump tenfold. ALWAYS. I've never seen another definition and I'm long, long time in this business.

Also first order has always been 6dB/octave (20dB/decade). That's how every signal filter is defined etc.

As for power cord. What you describe is average value. Amplifier might take 10A on average but it will be taken in narrow spikes of 100A or more, causing 10V drop on your 0.1ohm power cord equivalent to 20% drop in max power.

Capacitor inside is not discharging faster. The problem is that it discharges very little. If voltage drops from one peak of 120Hz full wave to the next only 50mV (ripple voltage) and amplitude is 50V then charging will be done only in arccos((50V-50mV)/50V)=2.6deg. Charging pulse will be 16.6ms*2.6deg/360deg=0.12ms. Pulses will be a little wider because of all inductance in the circuit but as Atmasphere said - in millisecond range.

Width of the pulse depends on the ripple (voltage drop) and ripple depends on the load. It is in a sense fixed frequency switching power supply that is polluting mains. Current spikes have high frequency content that propagates thru voltage drops to every other component on the same mains. Shielding and filtering becomes extremely important.

Jeff Rowland talks a little about it here: http://jeffrowlandgroup.com/kb/questions.php?questionid=144

As for tubes - I built 100W EL34 amp when I was 15 but vaguely remember that tubes need to be heated. This is the double duty Almarg mentioned and can be demanding one - at this moment Atmasphere ears are getting red because his amps (one of the best in the world) waste 90% of power on filament of current hungry tubes (2.5A per tube and there is a lot of them). If not for that, I would buy this amp in a jiffy.